1. V3 ctgx-4=-53. 2cos(3x-п/6)-V2=0

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вопрос

To solve the first equation:

ctg(x) = -49/4
tan(x) = -4/49
x = atan(-4/49) + n pi, where n is an integer
x ≈ -0.0808 + n pi

To solve the second equation:

2cos(3x - π/6) - √2 = 0
cos(3x - π/6) = √2/2
3x - π/6 = ±π/4 + 2nπ, where n is an integer
3x = π/4 + π/6 ± 2nπ or 3x = 7π/4 + π/6 ± 2nπ
x = (π/4 + π/6 ± 2nπ) / 3 or x = (7π/4 + π/6 ± 2nπ) / 3

Simplify further by substituting n = 0, 1, 2, etc., to find the exact values of x.