Fe + H2SO4 = ? уравнение реакции Какие продукты образуются в результате взаимодействия Fe + H2SO4 = ? Надо записать молекулярное и ионное уравнение реакции, а также решить задачу. Вот условие: какая масса соли образуется при растворении 10 г железа в 155 г раствора 40%-ной серной кислоты? Какое из веществ будет в избытке?

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Molecular equation: Fe + H2SO4 = FeSO4 + H2
Ionic equation: Fe + 2H+ + SO4^2- = Fe^2+ + SO4^2- + H2

To find the mass of the salt formed, we need to calculate the moles of Fe and H2SO4, and then determine the limiting reactant.

Calculate the moles of Fe:
molar mass of Fe = 55.85 g/mol
moles of Fe = mass / molar mass
moles of Fe = 10 g / 55.85 g/mol
moles of Fe = 0.179 mol

Calculate the moles of H2SO4:
First, calculate the mass of H2SO4 in the solution:
mass of H2SO4 = 0.40 * 155 g = 62 g
molar mass of H2SO4 = 98.08 g/mol
moles of H2SO4 = mass / molar mass
moles of H2SO4 = 62 g / 98.08 g/mol
moles of H2SO4 = 0.632 mol

Determine the limiting reactant:
From the balanced chemical equation, we see that 1 mole of Fe reacts with 1 mole of H2SO4.
The moles of Fe (0.179 mol) are less than the moles of H2SO4 (0.632 mol), so Fe is the limiting reactant.

Calculate the mass of FeSO4 formed:
From the balanced equation, 1 mole of Fe forms 1 mole of FeSO4.
molar mass of FeSO4 = 151.91 g/mol
mass of FeSO4 = moles of Fe molar mass
mass of FeSO4 = 0.179 mol 151.91 g/mol
mass of FeSO4 = 27.15 g

Therefore, 27.15 g of FeSO4 is formed when 10 g of Fe is dissolved in 155 g of 40% H2SO4 solution. H2SO4 is in excess in this reaction.